String.Replace가 "전체 단어"를 누르는 방법

String.Replace가 "전체 단어"를 누르는 방법

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이것을 가질 방법이 필요합니다.

"test, and test but not testing.  But yes to test".Replace("test", "text")

이것을 반환하십시오 :

"text, and text but not testing.  But yes to text"

기본적으로 전체 단어를 바꾸고 싶지만 부분 일치는 아닙니다.

참고 :이 작업에는 VB (SSRS 2008 코드)를 사용해야하지만 C #은 일반적인 언어이므로 둘 중 하나의 응답은 괜찮습니다.

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정규식은 가장 쉬운 방법입니다.

string input = "test, and test but not testing.  But yes to test";
string pattern = @"\btest\b";
string replace = "text";
string result = Regex.Replace(input, pattern, replace);
Console.WriteLine(result);

패턴의 중요한 부분은 \b단어 경계에서 일치 하는 메타 문자입니다. 대소 문자를 구분하지 않으려면 RegexOptions.IgnoreCase다음을 사용하십시오 .

Regex.Replace(input, pattern, replace, RegexOptions.IgnoreCase);

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Ahmad Mageed가 제안한 정규 표현식을 래핑 하는 함수 ( 여기 블로그 게시물 참조 )를 만들었습니다.

/// <summary>
/// Uses regex '\b' as suggested in https://stackoverflow.com/questions/6143642/way-to-have-string-replace-only-hit-whole-words
/// </summary>
/// <param name="original"></param>
/// <param name="wordToFind"></param>
/// <param name="replacement"></param>
/// <param name="regexOptions"></param>
/// <returns></returns>
static public string ReplaceWholeWord(this string original, string wordToFind, string replacement, RegexOptions regexOptions = RegexOptions.None)
{
    string pattern = String.Format(@"\b{0}\b", wordToFind);
    string ret=Regex.Replace(original, pattern, replacement, regexOptions);
    return ret;
}

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Sga가 언급했듯이 정규식 솔루션은 완벽하지 않습니다. 그리고 성능도 좋지 않은 것 같습니다.

내 공헌은 다음과 같습니다.

public static class StringExtendsionsMethods
{
    public static String ReplaceWholeWord ( this String s, String word, String bywhat )
    {
        char firstLetter = word[0];
        StringBuilder sb = new StringBuilder();
        bool previousWasLetterOrDigit = false;
        int i = 0;
        while ( i < s.Length - word.Length + 1 )
        {
            bool wordFound = false;
            char c = s[i];
            if ( c == firstLetter )
                if ( ! previousWasLetterOrDigit )
                    if ( s.Substring ( i, word.Length ).Equals ( word ) )
                    {
                        wordFound = true;
                        bool wholeWordFound = true;
                        if ( s.Length > i + word.Length )
                        {
                            if ( Char.IsLetterOrDigit ( s[i+word.Length] ) )
                                wholeWordFound = false;
                        }

                        if ( wholeWordFound )
                            sb.Append ( bywhat );
                        else
                            sb.Append ( word );

                        i += word.Length;
                    }

            if ( ! wordFound )
            {
                previousWasLetterOrDigit = Char.IsLetterOrDigit ( c );
                sb.Append ( c );
                i++;
            }
        }

        if ( s.Length - i > 0 )
            sb.Append ( s.Substring ( i ) );

        return sb.ToString ();
    }
}

... 테스트 케이스 포함 :

String a = "alpha is alpha";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alphonse" ) );
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alf" ) );

a = "alphaisomega";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );

a = "aalpha is alphaa";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );

a = "alpha1/alpha2/alpha3";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "xxx" ) );

a = "alpha/alpha/alpha";
Console.WriteLine ( a.ReplaceWholeWord ( "alpha", "alphonse" ) );

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I just want to add a note about this particular regex pattern (used both in the accepted answer and in ReplaceWholeWord function). It doesn't work if what you are trying to replace isn't a word.

Here a test case:

using System;
using System.Text.RegularExpressions;
public class Test
{
    public static void Main()
    {
        string input = "doin' some replacement";
        string pattern = @"\bdoin'\b";
        string replace = "doing";
        string result = Regex.Replace(input, pattern, replace);
        Console.WriteLine(result);
    }
}

(ready to try code: http://ideone.com/2Nt0A)

This has to be taken into consideration especially if you are doing batch translations (like I did for some i18n work).

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If you want to define what characters make up a word i.e. "_" and "@"

you could use my (vb.net) function:

 Function Replace_Whole_Word(Input As String, Find As String, Replace As String)
      Dim Word_Chars As String = "ABCDEFGHIJKLMNOPQRSTUVWYXZabcdefghijklmnopqrstuvwyxz0123456789_@"
      Dim Word_Index As Integer = 0
      Do Until False
         Word_Index = Input.IndexOf(Find, Word_Index)
         If Word_Index < 0 Then Exit Do
         If Word_Index = 0 OrElse Word_Chars.Contains(Input(Word_Index - 1)) = False Then
            If Word_Index + Len(Find) = Input.Length OrElse Word_Chars.Contains(Input(Word_Index + Len(Find))) = False Then
               Input = Mid(Input, 1, Word_Index) & Replace & Mid(Input, Word_Index + Len(Find) + 1)
            End If
         End If
         Word_Index = Word_Index + 1
      Loop
      Return Input
   End Function

Test

Replace_Whole_Word("We need to replace words tonight. Not to_day and not too well to", "to", "xxx")

Result

"We need xxx replace words tonight. Not to_day and not too well xxx"

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You could use the string.replace

string input = "test, and test but not testing.  But yes to test";
string result2 = input.Replace("test", "text");
Console.WriteLine(input);
Console.WriteLine(result2);
Console.ReadLine();

참고URL : https://stackoverflow.com/questions/6143642/way-to-have-string-replace-only-hit-whole-words